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[ZogoChieftan]

yourwishismine:
You mentioned that in the previous release of my toolbox there are some bugs in the config.xml file can you please tell me which tags are affected and what is the error that you get when you launch the application.
anyone:
Can someone please tell me the proper procedure for loading in xml files using vb.net cause i've tried and it's difficult.

From ZogoChieftan

[ZogoChieftan]

sounds good 2 me thanks.

[morpheous1777]

I know what ya mean, Ive been stumped for a while now on how to load an xml file in vb.net

[unleashx]

CODE

//Add reference to XML using System.Xml; ... XmlDocument doc = new XmlDocument(); //XmlString must contain a valid xml string doc.LoadXml(XmlString);

That's all there is to loading an xml.

To search for certain tags:

CODE

XmlNodeList xmlNList = doc.GetElementsByTagName("Image"); XmlElement listElement;    for (int i = 0; i< xmlNList.Count; i++)    {  listElement = xmlNList.Item(i) as XmlElement;  if (listElement != null)  {     //...do your thing     //you can use the GetAttribute method to query attributes. i.e.: listElement.GetAttribute("Source"));  }    }

I'm also using a generic function which you may find usefull

CODE

private XmlElement FindChildElement(XmlElement pElement, string ElementName, string AttributeValue, bool Detach) {    if (pElement == null || (ElementName == null || ElementName.Length == 0))  return null;    XmlNodeList xmlNList = pElement.SelectNodes(ElementName);     for (int i = 0; i   {  if (AttributeValue.Length >0)  {     //modify this code and loop thru available attributes     if (!xmlNList.Item(i).Attributes["Text"].Value.Equals(AttributeValue))    continue;  }  if (Detach)  {     XmlElement pReturn = xmlNList.Item(i).Clone() as XmlElement;     pElement.RemoveChild(xmlNList.Item(i));     return pReturn;  } else     return (xmlNList.Item(i) as XmlElement);    }    return null;   }

An example showing how to use the above code:

CODE

XmlElement listElement = null; //let's find the Menu element listElement = FindChildElement((doc.ChildNodes[0] as XmlElement), "Menu", "", false); //ChildNodes[0] is the root of the document //let's find the Submenu called 'Games" listElement = FindChildElement(listElement, "List", "Games", false);

Note: For brevity's sake, all error handlers have been removed.