xboxscene.org forums

Pages: 1 ... 6 7 [8] 9 10 ... 13

Author Topic: Riddles  (Read 1168 times)

veg

  • Archived User
  • Newbie
  • *
  • Posts: 29
Riddles
« Reply #105 on: January 14, 2004, 07:16:00 AM »
QUOTE (TCS @ Jan 13 2004, 05:42 PM)
QUOTE (TCS @ Jan 13 2004, 05:41 PM)
QUOTE (veg @ Jan 11 2004, 02:04 PM)
It's ten o'clock in the morning and a man and his dog set out on a walk to the next town. The man is able to walk at the constant rate of speed of 5MPH. In the mean time his dog takes off and runs ahead to the next town then turns around and heads back to the man. Then sets off for the town again. The dog keeps doing this until the man makes it to his destination at 12 noon. The dog was running at a constant speed of 15MPH.

Given: The man walked 10 miles.

How far did the dog travel?

Bonus question how many trips did the dog make?

hint: You have to ignore acceleration and deceleration.

The dog made 3 trips.

Make that 2 trips.

sorry nope
Logged

dcuk

  • Archived User
  • Newbie
  • *
  • Posts: 22
Riddles
« Reply #106 on: January 15, 2004, 06:27:00 AM »
QUOTE (xBaNaNaEv0LuTiOnx @ Jan 9 2004, 04:32 AM)
QUOTE (DuDeR MaN @ Jan 8 2004, 07:07 PM)
While sitting in her easy chair, drinking beer and watching a ball game, Bertha Dribble decided to turn over a new leaf.  She decided to get into shape.  Not one to make rash decisions, Bertha hollered out to her husband to go to the library and find her a book on physical fitness.  When Mr. Dribble got to the library he saw a book with "how to jog" on it's spine. He "snuck" it out and returned home.  When Bertha finally glanced at the book several weeks later, she found that it had nothing to do with getting into shape.  What kind of book was it?

a cook book?

Oh come on whats the answer to this cos its gonna drive me flipping crazy......................................................
My enitre processing power is going to be occupied by this every flipping moment of my waking day.
how could you do this to me ....... have you no consideration for my sanity ! !
Logged

eyric101

  • Archived User
  • Sr. Member
  • *
  • Posts: 283
Riddles
« Reply #107 on: January 15, 2004, 07:02:00 AM »
It was an encyclopedia. The book simply carried entries of words that begin with 'How' to words that begin with 'Jog'
Logged

DuDeR MaN

  • Archived User
  • Sr. Member
  • *
  • Posts: 475
Riddles
« Reply #108 on: January 15, 2004, 12:53:00 PM »
QUOTE (eyric101 @ Jan 15 2004, 12:02 PM)
It was an encyclopedia. The book simply carried entries of words that begin with 'How' to words that begin with 'Jog'

finally someone got it, good job.
Logged

Majinbuu

  • Archived User
  • Sr. Member
  • *
  • Posts: 266
Riddles
« Reply #109 on: January 16, 2004, 03:36:00 AM »
QUOTE (veg @ Jan 11 2004, 09:04 AM)
It's ten o'clock in the morning and a man and his dog set out on a walk to the next town. The man is able to walk at the constant rate of speed of 5MPH. In the mean time his dog takes off and runs ahead to the next town then turns around and heads back to the man. Then sets off for the town again. The dog keeps doing this until the man makes it to his destination at 12 noon. The dog was running at a constant speed of 15MPH.

Given: The man walked 10 miles.

How far did the dog travel?

Bonus question how many trips did the dog make?

hint: You have to ignore acceleration and deceleration.

Disregaurding accelleration and decelleration, the dog made an infinite number of trips.
Logged

Lorre

  • Archived User
  • Newbie
  • *
  • Posts: 41
Riddles
« Reply #110 on: January 16, 2004, 06:32:00 AM »
QUOTE (keenie @ Jan 16 2004, 11:28 AM)
You are given two pieces of identical string, each exactly 1 meter long, along with a box of matches. Each piece of string, burns for exactly one hour, albeit not constantly (ie one section of each string burns longer then another). You are then removed of any devices that enable you to tell the time. Your task, is to figure out how to measure 45 minutes, using just the two pieces of string!

Light both strings at the same time, but on the other site (since they don't burn equally you should be able to see which side burns faster than the other, but they still remain IDENTICAL) this way you'll have a string burning on the left side and one on the right site, when they cross eachother "halfway", half an hour has passed.
Blow them out and repeat the same process to make them burn 15 mins.
30+15=45

Came up with this all by my self biggrin.gif
Logged

maximillian

  • Archived User
  • Newbie
  • *
  • Posts: 12
Riddles
« Reply #111 on: January 16, 2004, 07:53:00 AM »
QUOTE (keenie @ Jan 16 2004, 11:28 AM)
You are given two pieces of identical string, each exactly 1 meter long, along with a box of matches. Each piece of string, burns for exactly one hour, albeit not constantly (ie one section of each string burns longer then another). You are then removed of any devices that enable you to tell the time. Your task, is to figure out how to measure 45 minutes, using just the two pieces of string!

Place the box of matches in your pocket - since matches are a useful item and they may come in handy some other day.  Now... use one of the pieces of string as a sundial.  Hang it from something and make sure that the free end touches the ground.  Starting at roughly 11:30am - mark the position of the sun (from the string-sundial) as time zero.  Burn the other piece of string.  After the hour has passed mark the one-hour position.  45 minutes is about 3/4 of the span between zero and one hour marks.  If you want to get technical about it then you could take the string that forms the pendulum and use it to accurately measure 1/4 of the span by folding it twice.

Simple... and you have a free box of matches.
Logged

veg

  • Archived User
  • Newbie
  • *
  • Posts: 29
Riddles
« Reply #112 on: January 16, 2004, 08:39:00 AM »
QUOTE (Wesly @ Jan 16 2004, 04:52 PM)
QUOTE
It's ten o'clock in the morning and a man and his dog set out on a walk to the next town. The man is able to walk at the constant rate of speed of 5MPH. In the mean time his dog takes off and runs ahead to the next town then turns around and heads back to the man. Then sets off for the town again. The dog keeps doing this until the man makes it to his destination at 12 noon. The dog was running at a constant speed of 15MPH.

Given: The man walked 10 miles.

How far did the dog travel?

Bonus question how many trips did the dog make?

hint: You have to ignore acceleration and deceleration.


The dog made 4 turns.
At the time of the 5th turn the dog arrived in town at the exact moment the man arrived (so there wasn't a 5th turn but the dog did make 5 runs).

So if you define a "trip" as a run from A to destination B (and not back again) then the dog made 5 trips.
If you define a "trip" as the way to destination included with the way back then the dog made 2,5 trips,......although the dog and man together actually made one trip (from home together to destination in this case to town).

Not the answer I had in mind sorry.

I was thinking round trips for the dog by the way.

Think about this:
In the dogs first round trip he will meet the man at the 5 mile mark between the towns. This is because the man is going 5 mph and the dog is going 15 mph at the 1 hr mark they meet at 5mi.
The second time the dog will meet the man the man will have traveled 2.5 more miles after 1/2 hrs more.
Without giving the answer I will also say the progression will continue until the dog can no longer turn around (for practical purposes). So you may figure the length of the dog in the calculation. A dog one foot in length is around .00019 of a mile...<grin>

veg
Logged

TCS

  • Archived User
  • Newbie
  • *
  • Posts: 34
Riddles
« Reply #113 on: January 16, 2004, 11:51:00 PM »
Jesus Christ that's not a fucking riddle.  That's something you gotta get Einstein or Hawking to figure out.
Logged

veg

  • Archived User
  • Newbie
  • *
  • Posts: 29
Riddles
« Reply #114 on: January 17, 2004, 02:01:00 AM »
LMAO...
Sheeit man it ain't that hard. Takes 2 min with a calculator.
I ain't no Einstein.
Here's how to get the answer.
If the dog meets the man at a halfway point each (round) trip.
The dog goes 15 mi for each 5 mi the man does.
The towns are 10 mi apart.
1st trip dog meets man @ 5mi the man has 5mi to go
2nd trip dog meets man @ 7.5 (5+2.5 mi ) the man has 2.5 mi to go
3rd trip 8.75 (5+2.5+1.25 mi )
4th trip 9.375 (5+2.5+1.25 +.625 mi) and so on.
If you can see you just divide 2 into the remainder each time
Average dog is 1ft for an ankle biter to around 3 ft or so.
Well use 1 ft for example. 1 mi is 5280 ft. divide 5280 into one you get dog length in miles. around .00019 mi

Keep dividing 2 into the remainder until you get below the length of the dog this is where the little ankle biter can't make any more trips.
This happens between 15 and 16 trips.

You want some Einstein shit what's the number of trips if the dog has no dimension (length) he he he...
Logged

DuDeR MaN

  • Archived User
  • Sr. Member
  • *
  • Posts: 475
Riddles
« Reply #115 on: January 17, 2004, 08:01:00 AM »
i personally agree that anything that involves a calculator is a math problem and not a riddle.  Riddle's tend to make you look at the unseen obvious.
Logged

ssjdave80

  • Archived User
  • Jr. Member
  • *
  • Posts: 71
Riddles
« Reply #116 on: January 17, 2004, 01:49:00 PM »
veg your dead.
Logged

brandogg

  • Archived User
  • Hero Member
  • *
  • Posts: 1668
Riddles
« Reply #117 on: January 18, 2004, 07:44:00 AM »
The dog made 1 trip.
Logged

TCS

  • Archived User
  • Newbie
  • *
  • Posts: 34
Riddles
« Reply #118 on: January 18, 2004, 05:09:00 PM »
QUOTE (veg @ Jan 17 2004, 07:01 PM)
I am a rock group that has 4 members, all of whom are dead, one of which was assasinated. What am I?

The Monkees.
Logged

ThreeEyedFish

  • Archived User
  • Newbie
  • *
  • Posts: 19
Riddles
« Reply #119 on: January 19, 2004, 04:33:00 AM »

What comes twice in a moment, once in a minute and never in a thousand years?
Logged
Pages: 1 ... 6 7 [8] 9 10 ... 13
« previous next »